I’m working my way through The C Programming Language at the moment, and so far I’m loving C’s purity and leanness.
One of my few disappointments with the book is the lack of solutions to the exercises. The exercises are refreshingly challenging because the book isn’t aimed at beginning programmers. Unfortunately this means that the desire to validate one’s solutions is quite strong. Fortunately, Google had a solution to this problem: Richard Heathfield’s solutions site.
I just finished my solution to exercise 1.23 (“Remove all comments from a C program”) and I’m quite chuffed with it so thought I would share it here. Out of the multiple solutions provided on Richard’s site, mine was about the closest to following the guidelines as far as what knowledge one is supposed to have of C by that (early) point in the book (the only thing I cheated with is the use of break
and continue
– it would have just been quite ugly without those two small additions). Basically the solution is a state machine using if / else
instead of more traditional switch
methods as switch
had not yet been introduced.
My solution deals with all the special cases I could think of, and even deals with the tricky sample input on Richard’s site, provided at the bottom of the solutions page for this exercise.
#include <stdio.h>
int main()
{
int c;
int c2;
int in_quotes = 0;
int in_comment = 0;
int current_quote;
c = getchar();
while (c != EOF)
{
if (!in_comment && !in_quotes)
{
if (c == '\'' || c == '"')
{
in_quotes = 1;
current_quote = c;
putchar(c);
}
else if (c == '/')
{
c2 = getchar();
if (c2 != EOF && c2 == '*')
{
in_comment = 1;
}
else
{
putchar(c);
c = c2;
continue;
}
}
else
{
putchar(c);
}
}
else if (in_comment)
{
if (c == '*')
{
c2 = getchar();
if (c2 != EOF && c2 == '/')
{
in_comment = 0;
}
else
{
c = c2;
continue;
}
}
}
else if (in_quotes)
{
if (c == '\\')
{
putchar(c);
c = getchar();
}
else
{
if (c == current_quote)
in_quotes = 0;
}
putchar(c);
}
c = getchar();
}
return 0;
}